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VB中实现MD5加密

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使用方法:

msgbox DigestStrToHexStr(111)

源代码:

Option Explicit

/******************************************************************************
* Copyright (C) 2000 by Robert Hubley. *
* All rights reserved. *
* *
* This software is provided ``AS IS and any express or implied *
* warranties, including, but not limited to, the implied warranties of *
* merchantability and fitness for a particular purpose, are disclaimed. *
* In no event shall the authors be liable for any direct, indirect, *
* incidental, special, exemplary, or consequential damages (including, but *
* not limited to, procurement of substitute goods or services loss of use, *
* data, or profits or business interruption) however caused and on any *
* theory of liability, whether in contract, strict liability, or tort *
* (including negligence or otherwise) arising in any way out of the use of *
* this software, even if advised of the possibility of such damage. *
* *
******************************************************************************

CLASS: md5

DESCRIPTION:
This is a class which encapsulates a set of MD5 Message Digest functions.
MD5 algorithm produces a 128 bit digital fingerprint (signature) from an
dataset of arbitrary length. For details see RFC 1321 (summarized below).
This implementation is derived from the RSA Data Security, Inc. MD5 Message-Digest
algorithm reference implementation (originally written in C)

AUTHOR:
Robert M. Hubley 12/1999


NOTES:
Network Working Group R. Rivest
Request for Comments: 1321 MIT Laboratory for Computer Science
and RSA Data Security, Inc.
April 1992


The MD5 Message-Digest Algorithm

Summary

This document describes the MD5 message-digest algorithm. The
algorithm takes as input a message of arbitrary length and produces
as output a 128-bit fingerprint or message digest of the input.
It is conjectured that it is computationally infeasible to produce
two messages having the same message digest, or to produce any
message having a given prespecified target message digest. The MD5
algorithm is intended for digital signature applications, where a
large file must be compressed in a secure manner before being
ncrypted with a private (secret) key under a public-key cryptosystem
such as RSA.

The MD5 algorithm is designed to be quite fast on 32-bit machines. In
addition, the MD5 algorithm does not require any large substitution
tables the algorithm can be coded quite compactly.

The MD5 algorithm is an extension of the MD4 message-digest algorithm
1,2. MD5 is slightly slower than MD4, but is more conservative in
design. MD5 was designed because it was felt that MD4 was perhaps
being adopted for use more quickly than justified by the existing
critical review because MD4 was designed to be exceptionally fast,
it is at the edge in terms of risking successful cryptanalytic
attack. MD5 backs off a bit, giving up a little in speed for a much
greater likelihood of ultimate security. It incorporates some
suggestions made by various reviewers, and contains additional
optimizations. The MD5 algorithm is being placed in the public domain
for review and possible adoption as a standard.

RFC AUTHOR:
Ronald L.Rivest
Massachusetts Institute of Technology
Laboratory for Computer Science
NE43 -324545 Technology Square
Cambridge, MA 02139-1986
Phone: (617) 253-5880
EMail: Rivest@ theory.lcs.mit.edu

Change HISTORY:

0.1.0 RMH 1999/12/29 Original version

Private Const OFFSET_4 = 4294967296#
Private Const MAXINT_4 = 2147483647

Private Const S11 = 7
Private Const S12 = 12
Private Const S13 = 17
Private Const S14 = 22
Private Const S21 = 5
Private Const S22 = 9
Private Const S23 = 14
Private Const S24 = 20
Private Const S31 = 4
Private Const S32 = 11
Private Const S33 = 16
Private Const S34 = 23
Private Const S41 = 6
Private Const S42 = 10
Private Const S43 = 15
Private Const S44 = 21


Private State(4) As Long
Private ByteCounter As Long
Private ByteBuffer(63) As Byte

Property Get RegisterA() As String
RegisterA = State(1)
End Property

Property Get RegisterB() As String
RegisterB = State(2)
End Property

Property Get RegisterC() As String
RegisterC = State(3)
End Property

Property Get RegisterD() As String
RegisterD = State(4)
End Property

Function to quickly digest a file into a hex string

Public Function DigestFileToHexStr(FileName As String) As String
Open FileName For Binary Access Read As #1
MD5Init
Do While Not EOF(1)
Get #1, , ByteBuffer
If Loc(1) LOF(1) Then
ByteCounter = ByteCounter + 64
MD5Transform ByteBuffer
End If
Loop
ByteCounter = ByteCounter + (LOF(1) Mod 64)
Close #1
MD5Final
DigestFileToHexStr = GetValues
End Function


Function to digest a text string and output the result as a stringb of hexadecimal characters.

Public Function DigestStrToHexStr(SourceString As String) As String
MD5Init
MD5Update Len(SourceString), StringToArray(SourceString)
MD5Final
DigestStrToHexStr = GetValues
End Function


A utility function which converts a string into an array of bytes.

Private Function StringToArray(InString As String) As Byte()
Dim I As Integer
Dim bytBuffer() As Byte
ReDim bytBuffer(Len(InString))
For I = 0 To Len(InString) - 1
bytBuffer(I) = Asc(Mid(InString, I + 1, 1))
Next I
StringToArray = bytBuffer
End Function


Concatenate the four state vaules into one string

Public Function GetValues() As String
GetValues = LongToString(State(1)) LongToString(State(2)) LongToString(State(3)) LongToString(State(4))
End Function


Convert a Long to a Hex string

Private Function LongToString(Num As Long) As String
Dim a As Byte
Dim b As Byte
Dim c As Byte
Dim d As Byte

a = Num And HFF
If a 16 Then
LongToString = 0 Hex(a)
Else
LongToString = Hex(a)
End If

b = (Num And HFF00) 256
If b 16 Then
LongToString = LongToString 0 Hex(b)
Else
LongToString = LongToString Hex(b)
End If

c = (Num And HFF0000) 65536
If c 16 Then
LongToString = LongToString 0 Hex(c)
Else
LongToString = LongToString Hex(c)
End If

If Num 0 Then
d = ((Num And H7F000000) 16777216) Or H80
Else
d = (Num And HFF000000) 16777216
End If

If d 16 Then
LongToString = LongToString 0 Hex(d)
Else
LongToString = LongToString Hex(d)
End If

End Function


Initialize the class This must be called before a digest calculation is started

Public Sub MD5Init()
ByteCounter = 0
State(1) = UnsignedToLong(1732584193#)
State(2) = UnsignedToLong(4023233417#)
State(3) = UnsignedToLong(2562383102#)
State(4) = UnsignedToLong(271733878#)
End Sub


md5 Final

Public Sub MD5Final()
Dim dblBits As Double

Dim padding(72) As Byte
Dim lngBytesBuffered As Long

padding(0) = H80

dblBits = ByteCounter * 8

Pad out
lngBytesBuffered = ByteCounter Mod 64
If lngBytesBuffered = 56 Then
MD5Update 56 - lngBytesBuffered, padding
Else
MD5Update 120 - ByteCounter, padding
End If


padding(0) = UnsignedToLong(dblBits) And HFF
padding(1) = UnsignedToLong(dblBits) 256 And HFF
padding(2) = UnsignedToLong(dblBits) 65536 And HFF
padding(3) = UnsignedToLong(dblBits) 16777216 And HFF
padding(4) = 0
padding(5) = 0
padding(6) = 0
padding(7) = 0

MD5Update 8, padding
End Sub


Break up input stream into 64 byte chunks

Public Sub MD5Update(InputLen As Long, InputBuffer() As Byte)
Dim II As Integer
Dim I As Integer
Dim J As Integer
Dim K As Integer
Dim lngBufferedBytes As Long
Dim lngBufferRemaining As Long
Dim lngRem As Long

lngBufferedBytes = ByteCounter Mod 64
lngBufferRemaining = 64 - lngBufferedBytes
ByteCounter = ByteCounter + InputLen
Use up old buffer results first
If InputLen = lngBufferRemaining Then
For II = 0 To lngBufferRemaining - 1
ByteBuffer(lngBufferedBytes + II) = InputBuffer(II)
Next II
MD5Transform ByteBuffer

lngRem = (InputLen) Mod 64
The transfer is a multiple of 64 lets do some transformations
For I = lngBufferRemaining To InputLen - II - lngRem Step 64
For J = 0 To 63
ByteBuffer(J) = InputBuffer(I + J)
Next J
MD5Transform ByteBuffer
Next I
lngBufferedBytes = 0
Else
I = 0
End If

Buffer any remaining input
For K = 0 To InputLen - I - 1
ByteBuffer(lngBufferedBytes + K) = InputBuffer(I + K)
Next K

End Sub


md5 Transform

Private Sub MD5Transform(Buffer() As Byte)
Dim x(16) As Long
Dim a As Long
Dim b As Long
Dim c As Long
Dim d As Long

a = State(1)
b = State(2)
c = State(3)
d = State(4)

Decode 64, x, Buffer

Round 1
FF a, b, c, d, x(0), S11, -680876936
FF d, a, b, c, x(1), S12, -389564586
FF c, d, a, b, x(2), S13, 606105819
FF b, c, d, a, x(3), S14, -1044525330
FF a, b, c, d, x(4), S11, -176418897
FF d, a, b, c, x(5), S12, 1200080426
FF c, d, a, b, x(6), S13, -1473231341
FF b, c, d, a, x(7), S14, -45705983
FF a, b, c, d, x(8), S11, 1770035416
FF d, a, b, c, x(9), S12, -1958414417
FF c, d, a, b, x(10), S13, -42063
FF b, c, d, a, x(11), S14, -1990404162
FF a, b, c, d, x(12), S11, 1804603682
FF d, a, b, c, x(13), S12, -40341101
FF c, d, a, b, x(14), S13, -1502002290
FF b, c, d, a, x(15), S14, 1236535329

Round 2
GG a, b, c, d, x(1), S21, -165796510
GG d, a, b, c, x(6), S22, -1069501632
GG c, d, a, b, x(11), S23, 643717713
GG b, c, d, a, x(0), S24, -373897302
GG a, b, c, d, x(5), S21, -701558691
GG d, a, b, c, x(10), S22, 38016083
GG c, d, a, b, x(15), S23, -660478335
GG b, c, d, a, x(4), S24, -405537848
GG a, b, c, d, x(9), S21, 568446438
GG d, a, b, c, x(14), S22, -1019803690
GG c, d, a, b, x(3), S23, -187363961
GG b, c, d, a, x(8), S24, 1163531501
GG a, b, c, d, x(13), S21, -1444681467
GG d, a, b, c, x(2), S22, -51403784
GG c, d, a, b, x(7), S23, 1735328473
GG b, c, d, a, x(12), S24, -1926607734

Round 3
HH a, b, c, d, x(5), S31, -378558
HH d, a, b, c, x(8), S32, -2022574463
HH c, d, a, b, x(11), S33, 1839030562
HH b, c, d, a, x(14), S34, -35309556
HH a, b, c, d, x(1), S31, -1530992060
HH d, a, b, c, x(4), S32, 1272893353
HH c, d, a, b, x(7), S33, -155497632
HH b, c, d, a, x(10), S34, -1094730640
HH a, b, c, d, x(13), S31, 681279174
HH d, a, b, c, x(0), S32, -358537222
HH c, d, a, b, x(3), S33, -722521979
HH b, c, d, a, x(6), S34, 76029189
HH a, b, c, d, x(9), S31, -640364487
HH d, a, b, c, x(12), S32, -421815835
HH c, d, a, b, x(15), S33, 530742520
HH b, c, d, a, x(2), S34, -995338651

Round 4
II a, b, c, d, x(0), S41, -198630844
II d, a, b, c, x(7), S42, 1126891415
II c, d, a, b, x(14), S43, -1416354905
II b, c, d, a, x(5), S44, -57434055
II a, b, c, d, x(12), S41, 1700485571
II d, a, b, c, x(3), S42, -1894986606
II c, d, a, b, x(10), S43, -1051523
II b, c, d, a, x(1), S44, -2054922799
II a, b, c, d, x(8), S41, 1873313359
II d, a, b, c, x(15), S42, -30611744
II c, d, a, b, x(6), S43, -1560198380
II b, c, d, a, x(13), S44, 1309151649
II a, b, c, d, x(4), S41, -145523070
II d, a, b, c, x(11), S42, -1120210379
II c, d, a, b, x(2), S43, 718787259
II b, c, d, a, x(9), S44, -343485551


State(1) = LongOverflowAdd(State(1), a)
State(2) = LongOverflowAdd(State(2), b)
State(3) = LongOverflowAdd(State(3), c)
State(4) = LongOverflowAdd(State(4), d)

/* Zeroize sensitive information.
*/
MD5_memset ((POINTER)x, 0, sizeof (x))

End Sub

Private Sub Decode(Length As Integer, OutputBuffer() As Long, InputBuffer() As Byte)
Dim intDblIndex As Integer
Dim intByteIndex As Integer
Dim dblSum As Double

intDblIndex = 0
For intByteIndex = 0 To Length - 1 Step 4
dblSum = InputBuffer(intByteIndex) + _
InputBuffer(intByteIndex + 1) * 256# + _
InputBuffer(intByteIndex + 2) * 65536# + _
InputBuffer(intByteIndex + 3) * 16777216#
OutputBuffer(intDblIndex) = UnsignedToLong(dblSum)
intDblIndex = intDblIndex + 1
Next intByteIndex
End Sub


FF, GG, HH, and II transformations for rounds 1, 2, 3, and 4.
Rotation is separate from addition to prevent recomputation.

Private Function FF(a As Long, _
b As Long, _
c As Long, _
d As Long, _
x As Long, _
s As Long, _
ac As Long) As Long
a = LongOverflowAdd4(a, (b And c) Or (Not (b) And d), x, ac)
a = LongLeftRotate(a, s)
a = LongOverflowAdd(a, b)
End Function

Private Function GG(a As Long, _
b As Long, _
c As Long, _
d As Long, _
x As Long, _
s As Long, _
ac As Long) As Long
a = LongOverflowAdd4(a, (b And d) Or (c And Not (d)), x, ac)
a = LongLeftRotate(a, s)
a = LongOverflowAdd(a, b)
End Function

Private Function HH(a As Long, _
b As Long, _
c As Long, _
d As Long, _
x As Long, _
s As Long, _
ac As Long) As Long
a = LongOverflowAdd4(a, b Xor c Xor d, x, ac)
a = LongLeftRotate(a, s)
a = LongOverflowAdd(a, b)
End Function

Private Function II(a As Long, _
b As Long, _
c As Long, _
d As Long, _
x As Long, _
s As Long, _
ac As Long) As Long
a = LongOverflowAdd4(a, c Xor (b Or Not (d)), x, ac)
a = LongLeftRotate(a, s)
a = LongOverflowAdd(a, b)
End Function


Rotate a long to the right

Function LongLeftRotate(value As Long, bits As Long) As Long
Dim lngSign As Long
Dim lngI As Long
bits = bits Mod 32
If bits = 0 Then LongLeftRotate = value: Exit Function
For lngI = 1 To bits
lngSign = value And HC0000000
value = (value And H3FFFFFFF) * 2
value = value Or ((lngSign 0) And 1) Or (CBool(lngSign And _
H40000000) And H80000000)
Next
LongLeftRotate = value
End Function


Function to add two unsigned numbers together as in C.Overflows are ignored!

Private Function LongOverflowAdd(Val1 As Long, Val2 As Long) As Long
Dim lngHighWord As Long
Dim lngLowWord As Long
Dim lngOverflow As Long

lngLowWord = (Val1 And HFFFF) + (Val2 And HFFFF)
lngOverflow = lngLowWord 65536
lngHighWord = (((Val1 And HFFFF0000) 65536) + ((Val2 And HFFFF0000) 65536) + lngOverflow) And HFFFF
LongOverflowAdd = UnsignedToLong((lngHighWord * 65536#) + (lngLowWord And HFFFF))
End Function


Function to add two unsigned numbers together as in C.Overflows are ignored!

Private Function LongOverflowAdd4(Val1 As Long, Val2 As Long, val3 As Long, val4 As Long) As Long
Dim lngHighWord As Long
Dim lngLowWord As Long
Dim lngOverflow As Long

lngLowWord = (Val1 And HFFFF) + (Val2 And HFFFF) + (val3 And HFFFF) + (val4 And HFFFF)
lngOverflow = lngLowWord 65536
lngHighWord = (((Val1 And HFFFF0000) 65536) + _
((Val2 And HFFFF0000) 65536) + _
((val3 And HFFFF0000) 65536) + _
((val4 And HFFFF0000) 65536) + _
lngOverflow) And HFFFF
LongOverflowAdd4 = UnsignedToLong((lngHighWord * 65536#) + (lngLowWord And HFFFF))
End Function


Convert an unsigned double into a long

Private Function UnsignedToLong(value As Double) As Long

If value 0 Or value = OFFSET_4 Then Error 6 Overflow
If value = MAXINT_4 Then
UnsignedToLong = value
Else
UnsignedToLong = value - OFFSET_4
End If
End Function


Convert a long to an unsigned Double

Private Function LongToUnsigned(value As Long) As Double
If value 0 Then
LongToUnsigned = value + OFFSET_4
Else
LongToUnsigned = value
End If
End Function



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华哥终于要面对加密这一问题了
Being a devil is the same as being a human. We should be kind. If we are kind, we are not a devil, we are a hybrid.
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肥牛的石头?出什么事了?
Being a devil is the same as being a human. We should be kind. If we are kind, we are not a devil, we are a hybrid.
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这个不适合我用,这个算法是不可逆的,也就是说1+4=5, 2+3=5 ,那到底明文是1,4还是2,3呢?

我需要的是可逆的算法,明文加密成密文后,还需要将密文还原成原文。。。
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